-4.9x^2+9x+2=0

Solution for -4.9x^2+9x+2=0 equation:

-4.9x^2+9x+2=0

a = -4.9; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·(-4.9)·2
Δ = 120.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{120.2}}{2*-4.9}=\frac{-9-\sqrt{120.2}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{120.2}}{2*-4.9}=\frac{-9+\sqrt{120.2}}{-9.8}
$